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Yahoo!奇摩知識+ - 分類問答 - 科學常識 - 已解決
Yahoo!奇摩知識+ - 分類問答 - 科學常識 - 已解決 
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高一 數學不等式
Oct 1st 2013, 13:50

ax^2 - 2ax + ( 2a -3) < 0 無實數解 代表 ax^2 - 2ax + ( 2a -3)≧0

所以

(1) 開口向上 ==> a＞0

(2) 此拋物線與 x軸最多一個交點

所以判別式= ( -2a )^2 -4a ( 2a -3)≦0

a( 2a -3)-a^2≧0

a^2-3≧0

a(a-3) ≧0 , a≦0 or  a≧3  與a＞0交集，得：a≧3


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